a] Force on a current carrying wire due to a magnetic field is given by:
where is the angle between the wire and the external magnetic field.
for the first part: = 0o and so F = BILsin(0) = 0 N
b] = 90o
6 = B(8.7)(0.35)sin90o
=> B = 1.97 T in the negative z direction.
NEED BOTH PARTS wire of length 0.35 m is conducting a current of I = 8.7...
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