Question

Problem 1) Solve parts d and e

Also given : Magnitude of force on the wire = Fb = 90N, in B= 3.0T i

1. A L-5.0 m piece of wire carrying a current I = 6.0 A runs along the-j direction. It has an x coordinate of 0 m, and is at a height of z = 1.0 m above the origin. 2-d view 3-d view +z +Z tx (d) (2 pts) The center of the wire is tethered to the origin with a 1.0 m piece of non- conducting string ( 1 m k. Calculate the torque about the origin (magnitude and direction) due to the magnetic force on the wire. (e) (2 pts) The wire is turned so that it now points along +i. What is the magnitude and direction of the resulting magnetic force on the wire?

Answer 1

Force acting on wire is along positive z axis of

magnitude 90 Nm

As torque is r x F .. cross product of r and F

It is zero as force and r have same direction

If wire is turned along +i or positive x axis then magnetic force acting on it is 0 .

As F = I(L xB)

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