Calculate the standard potential for the half-reaction:
Pd(OH)2(s) + 2 e- --> Pd(s) + 2OH-
Given that Ksp for Pd(OH)2 is 3.0x10-28 and the standard reduction potential for Pd2+ is: Pd2+ + 2e- --> Pd(s)
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Calculate the standard potential for the half-reaction: Pd(OH)2(s) + 2 e- --> Pd(s) + 2OH- Given...
Calculate for the half-reaction Pd(OH)2(s) + 2e = Pd(s) + 2OH' given that K(Pd(OH)2) = 3.00 x 10-28 and Ex = 0.915 V for the reaction Pd2 +2e=Pd(s) a. -0.875 V b. 0.101 V C. -0.795 V d. 0.256 V
Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions. H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e− 12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g) Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e− 2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq)2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq) Fe(s)⟶Fe2+(aq)+2e−Fe(s)⟶Fe2+(aq)+2e− oxidation reduction reduction oxidation reduction
. Given the reaction Mn2+ + 2OH- = Mn(OH)2 (s), calculate the pH required to decrease the manganese concentration (in the form of Mn2+) in a water supply to 0.03 mg/L. Note that the solubility product Ksp = 8×10-14.
calculate the initial pH of the solution given the following
reaction.
Ca(OH)2 -> Ca2+ + 2OH- with ksp= 1.3 x 10^-6
please explain how you got your answer.
15) (5 pts) Calculate the initial pH of the solution given the following reaction and equilibrium information below: Ca(OH),(s) = Ca2+ (aq) + 20H- (aq) with Ksp = 1.3 x 10-6 A) 8.2 B) 10.3 C) 11.8 D) 12.1 E) None of these are correct + Ann
Selective Reduction The standard reduction potential for the half-reaction: Sn4+ + 2e - Sn2+ is +0.15 V. Consider data from the table of standard reduction potentials for common half-reactions, in your text. For a galvanic cell under standard conditions, which of the following anodic half reactions would produce, at the cathode a spontaneous reduction of Sn4+ to Sn2+ but not Sn2+ to Sn. no yes yes yes yes yes Fe — Fe2+ + 2e- Sn2+ Sn4+ + 2e- Sn Sn2+...
A rechargeable nickel-cadmium (NiCd) battery contains the following half-reactions: NiO2 +2H2O(l)+2e– → Ni(OH)2 +2OH– E0 =0.49V Cd(OH)2 +2e– →Cd(s)+2OH– E0 =–0.81V a. What is the standard cell potential or voltage of this NiCd cell? b. Write the net chemical reaction in the direction of spontaneous reaction. Is cadmium oxidized or reduced? c. Write an expression for the reaction quotient Q. What is Q if the electrolyte concentrations are: [NiO2] = 1 M and [Cd(OH)2] = 0.01M and [Ni(OH)2] = 0.001...
Calculate the standard reduction potential for the half-reaction AgBr(s)+e−→Ag(s)+Br−(aq) Express the potential to two decimal places.
Oxidation half-reaction: Zn (s) + 2 OH- (aq) Z ZnO (s) + H20 (1) +2 € €°ox = +1.28 V Reduction half-reaction: 2 MnO2 (s) + H20 (1) + 2 € Mn203 (s) + 2OH- (aq) Ered = +0.15 V Ch9: Q22 Homework • Unanswered Given the half-reaction potentials above, what is the total cell potential of an alkaline battery in volts (V)? Numeric Answer: Unanswered Submit
A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential Fe+3(aq) +e− → Fe+2(aq) =E0red+0.771V 2H2O(l) +2e− → H2(g) + 2OH−(aq) =E0red−0.83V Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at the cathode. Write a balanced equation for the half-reaction that happens at the anode. Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written. Do you...
2. Using the information provided, calculate the standard cell potential, Eºcell, for the reaction below: Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe(s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq) E° (V) -0.74 -0.440 +0.771 +0.154 3Sn(aq) +2Cr(s) →2Cr" (aq) +35n²+ (aq)