Question

Calculate for the half-reaction Pd(OH)2(s) + 2e = Pd(s) + 2OH given that K(Pd(OH)2) = 3.00 x 10-28 and Ex = 0.915 V for the
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Solution given Reaction edcon theo pless + 2018 given kap for polcoho = 3x10 28 E = 0.915 pd +2 + 200 - polus) use To calculaKap = [pdf] [ OHI Standard condition for the half deaction - PdcOH) 48) +2 = P2087+2012 at starkand - [CH] = im Now [[Pd+2] =now we get Eipdoriaus = £°– 0-0591 dog ca. n œ - it is reaction quotient is a quantity that provides_a_measurement of the rel

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Calculate for the half-reaction Pd(OH)2(s) + 2e = Pd(s) + 2OH' given that K(Pd(OH)2) = 3.00...
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