Galvanic Cell and Voltage output using these elements. Copper Lead Please show all work and method to determine the output.
The reactions
Cu2+ + 2 e− <--->Cu(s) +0.337
Pb2+ + 2 e− <---> Pb(s) −0.126
the most negative oxidizes so must be inverted
Cu2+ + e− <---> Cu+ +0.337
Pb(s) <--->Pb2+ + 2 e− 0.126
E°cell = 0.337+0.126 = 0.463
The reaction
Cu2+(Aq) + Pb(s) ---> Cu(s) + Pb+2(aq)
Galvanic Cell and Voltage output using these elements. Copper Lead Please show all work and method...
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