what is the freezing point of the solution if we dissolve 1.10 g of iodine (I2...
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what is the freezing point of the solution if we dissolve 1.10
g of iodine (I2...
calculate the melting point in Celsius of a solution that is 4.37% benzene (C6H6 molar mass...
calculate the melting point in Celsius of a solution that is 4.37% benzene (C6H6 molar mass 78.108 g/mol) by mass in carbon tetrachloride. the normal melting point of CCl4 is -22.9 Celsius and Kf= 29.9 C/m thank you!
What is the freezing point of a solution made 1.31 mol of CHCl3 in 530.0 g...
What is the freezing point of a solution made 1.31 mol of CHCl3 in 530.0 g of CCl4 (Kf = 29.8 °C/m, Tf = -22.9 °C)?
A solution of 1.5 g benzoic acid (C6H5COOH; MW = 122.123 g/mol) in 100.0 g of...
A solution of 1.5 g benzoic acid (C6H5COOH; MW = 122.123 g/mol) in 100.0 g of carbon tetrachloride (CCl4; MW =153.822 g/mol) has a boiling point of 77.50°C. The boiling point of pure carbon tetrachloride is 76.72°C and the melting point is -22.92°C. Calculate the molecular weight of benzoic acid in the solution. Suggest a reason for the difference between the molar mass based on the formula (listed above) and the molar mass determined in part a.
The freezing point of pure lauric acid was measured. Then the freezing point of a solution...
The freezing point of pure lauric acid was measured. Then the freezing point of a solution of 4.003 g of lauric acid with 0.399g of unknown was measured. Determine the molar mass of the unknown. Kf for lauric acid = 4.4 °C/m. Freezing point of Lauric acid =44°C Freezing point of Unknown= 39°C
1) Calculate the freezing point (°C) of a solution of 50 mL of acetone (CH3COCH3, Molar...
1) Calculate the freezing point (°C) of a solution of 50 mL of acetone (CH3COCH3, Molar Mass = 58.08 g/mol, density 0.784 g/cm3) in 150g of CCl4, whose normal freezing point is -23.0 °C. Given: P = 1 atm, Kf CCl4 = 29.8 °C/m. Please show work. ------------------------------------------------------------------------------------------- 2) Calculate the boiling point (°C) at P = 1 atm of a solution of 25 g of acetone in 100 g of camphor whose normal boiling point is 204 °C. Kb...
Calculate the freezing point of a solution of 40.0 g of calcium chloride (molar mass =...
Calculate the freezing point of a solution of 40.0 g of calcium chloride (molar mass = 110.98 g/mol), dissolved in 800. g of benzene, C6H6. Kf for benzene is 5.10oC/m and the freezing point is 5.50oC for benzene.
What is the freezing point (in K) of a solution made by dissolving 19.831g of CCl4...
What is the freezing point (in K) of a solution made by dissolving 19.831g of CCl4 in 130.0 g of benzene? Pure benzene has a freezing point of 5.5°C and a Kf = 5.12 °C/m. Write your answer in Kelvin with 4 sig figs!
1.0345 g of palmitic acid dissolved in 8.7545 g of stearic acid. Calculate the freezing point...
1.0345 g of palmitic acid dissolved in 8.7545 g of stearic acid. Calculate the freezing point of the solution. The molar mass of palmitic acid is 256.48 g/ mol. The molal freezing point constant , Kf for stearic acid is 4.5 degrees C/ m and pure stearic acid freezes at 69.3 degrees Celsius.
Determine the freezing point of a solution that contains 29.5 g of iodine dissolved in 109...
Determine the freezing point of a solution that contains 29.5 g of iodine dissolved in 109 mL of ethanol (d = 0.789 g/mL). Pure ethanol has a melting point of -114.0 degree C and a freezing point depression constant of -1.99 degree C/m.
Suppose that we dissolve enough sugar in 100.0 g H2O to cause the solution to have...
Suppose that we dissolve enough sugar in 100.0 g H2O to cause the solution to have a freezing point of -3.20°C. How many grams of water must we add to the solution so that the freezing point will be - 1.00°C? For water, Kf = 1.86°C/m.
What is the freezing point of a solution made 1.31 mol of CHCl3 in 530.0 g of CCl4 (Kf = 29.8 °C/m, Tf = -22.9 °C)?
Determine the freezing point of a solution that contains 29.5 g of iodine dissolved in 109 mL of ethanol (d = 0.789 g/mL). Pure ethanol has a melting point of -114.0 degree C and a freezing point depression constant of -1.99 degree C/m.
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