How many calories are needed to convert 125 grams of water at 75.0 C to steam at 100.0 C?
[Specific heats: ice = 0.495, water = 1.00 steam = 0.478 cal/g C]
[water's heat of fusion = 80.0 cal/gram, water's heat of vaporization - 540.0 cal/gram]
3125 cal
3330 cal
6875 cal
13,125 cal
70,625 cal
How many calories are needed to convert 125 grams of water at 75.0 C to steam at 100.0 C?
Ice at -42 C was warmed to steam at 134 C. How much energy, in calories, was gained to warm 250 g of ice to steam? (get the sign right!) Specific heat H2O(g) = 0.48 cal/gram-C, Specific heat H2O(s) = 0.5 cal/gram-C. Specific heat H2O(l) = 1.0 cal/gram-C. Heat of vaporization H2O = 540 cal/gram, Heat of fusion H2O = 80 cal/gram.
How do I solve the following questions (Step by Step) (1). Calculate the heat required to convert 10.0 g of ice at 0.0 °C to steam at 100.0 °C. The specific heat of water is 1.00 cal/(g x °C); the heat of fusion is 80.0 cal/g; and the heat of vaporization is 540.0 cal/g. (2). What is the molar mass of trinitrotoluene (TNT), C7H5N3O6 (3). What is the percentage of water in NiCl2 2H2O? (4). Shapes of the following molecules...
7) Give the heating curve (4 pts) and calculate the heat in KJ (9 pts) needed to convert 175.0 grams of liquid water at 47.4 degrees C to steam at 177 degrees C. The specific heat of ice, water, and steam are 0.48. 1.00, 0.49 calories/g °C respectively. The heat of vaporization of water is 540.0 cal/g and the heat of fusion of water is 80.0 cal/g, you may or may not need to use all of these values] Remember...
18 grams of ice at –31°C is to be changed to steam at 199°C. The entire process requires _____ cal. Round your answer to the nearest whole number. The specific heat of both ice and steam is 0.5 cal/g°C. The specific heat of water is 1.00 cal/gK. The heat of fusion is 80 cal/g and the heat of vaporization is 540 cal/g.
Q13) 17 grams of ice at –35°C is to be changed to steam at 179°C. The entire process requires _____ cal. Round your answer to the nearest whole number. The specific heat of both ice and steam is 0.5 cal/g°C. The specific heat of water is 1.00 cal/gK. The heat of fusion is 80 cal/g and the heat of vaporization is 540 cal/g.
4) Give the molecular equation, the complete ionic equation and the net ionic equation to consult your solubility chart) Potassium phosphate + magnesium acetate -------- Molecular Eq (3pts) = ALTO Complete ionic eq (3 pts) = Net ionic eq (3 pts) = 5) Give the heating curve (4 pts) and calculate the heat in KJ (9 pts) needed to convert 56.8 grams of ice at -33.3 degrees C to liquid water at 66.9 degrees C. The specific heat of ice,...
Prob. 2: Cooling Curve Circle: Emathermier Exothermis?) Cale, the amount of heat this time in calories (cal) - Ilse I cal 4184 for conversions) lost or removed From 1.75 mol water as steam at a convert it to solid ice chilled in a freezer to a temperature of 47.2°C Cumulative Heat Lost To do this, follow the above drawn curve to determine the amount of heat lost for each of the five steps of this process to convert superheated steam...
How much energy is required to convert 100 g of ice at -17 °C to water at 52°C? Specific heat of Ice = 0.5 cal/g°C Heat of fusion of ice is 80 cal/g Specific heat of Water = 1.0 cal/g°C Heat of vaporization of water is 540 cal/g Specific heat of Steam = 0.5 cal/g°C Question 18 3 pts Lactated Ringer's solution, is a mixture of sodium chloride, sodium lactate, potassium chloride and calcium chloride in water. It is an...
How many grams of steam at 100C are required to melt 200 grams of ice? Heat fusion for ice at 0C is 334J/g. Heat of vaporization of water at 100C is 2,230J/g.
Enter your answer in the provided box. How much heat (in kJ) is needed to convert 916 g of ice at -10.0°C to steam at 126.0°C? (The specific heats of ice, water, and steam are 2.03 J/g . oC, 4.184 J/g . oC, and 1.99 J/g , oC, respectively. The heat of fusion of water is 6.01 kJ/mol, the heat of vaporization is 40.79 k.J/mol.) k.J