Enter your answer in the provided box. How much heat (in kJ) is needed to convert...

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Answer 1

Answer #1

q = q1 + q2 + q3 + q4 + q5

q = (mC_ice $\Delta$ T) + (m $\Delta$ H_fus) + (mC_water $\Delta$ T) + (m $\Delta$ H_vap) + (mC_vap $\Delta$ T)

q = (916 x 2.03 x 10) + (916 x 333.9) + (916 x 4.184 x 100) + (916 x 2266) + (916 x 1.99 x 26)

q = 18594.8 + 305852.4 + 383254.4 + 2075656 + 47393.84

q = 2830751 J

q = 2830 kJ

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Answer 2

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