omework i 1 attempt left Check my work Enter your answer in the provided box. Calculate...

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Answer 1

Answer #1

mass of steam = 71.5 g

moles of steam = 71.5 / 18.015 = 3.97 mol

125 --------- 100 ------------ 58

Q1 = m Cp dT

= 71.5 x 1.99 x (125 - 100)

= 3557.125 J

Q2 = n x delta Hvap

= 3.97 x 40.79 x 10^3

= 161936.3 J

Q3 = 71.5 x 4.184 x (100 - 58)

= 12564 J

total heat = Q1 + Q2 + Q3

= 178058 J

heat released = 178 kJ

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Answer 2

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