An engineer commutes daily from her suburban home to her midtown office. The average time for a oneway trip is 32 minutes, with a standard deviation of 4.1 minutes. Assume the distribution of trip times to be normally distributed.
a) What is the probability that a trip will take at least 35 minutes?
b) Find the probability that exactly 4 of the next 5 trips will take at least 35 minutes.
a) P(X > 35) = P((X - mean)/sd > (35 - mean)/sd)
= P(Z > (35 - 32)/4.1)
= P(Z > 0.73)
= 1 - P(Z < 0.73)
= 1 - 0.7673
= 0.2327
b) n = 5
p = 0.2327
P(X = x) = nCx * px * (1 - p)n - x
P(X = 4) = 5C4 * (0.2327)^4 * (1 - 0.2327)^1
= 0.0112
An engineer commutes daily from her suburban home to her midtown office. The average time for...
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