6. You’ve been tasked to evaluate an existing piece of machinery.You collected the following data:
Today
One Year Two Years Three Years Four Years Five Years Six Years
Seven Years Eight Years Nine Years Ten Years
Salvage Value
$20,000 $10,000 $5,000 $2,500 $1,000 $500 $250 $0.00 $0.00 $0.00 $0.00
Annual MX Cost
$1,000 $2,000 $3,000 $4,000 $5,000 $6,000 $7,000 $8,000 $9,000
$10,000
What is the useful life of the existing piece of machinery? Cost of capital is 4%. Hint calculate EUAC at Years Six, Seven and Eight.
EUAC for 6 yrs = 20000 * (A/P,4%,6) + 1000 + 1000 * (A/G,4%,6) - 250 * (A/F,4%,6)
= 20000 *0.190762 + 1000 + 1000 *2.385715 - 250 *0.150762
= 7163.26
EUAC for 7 yrs = 20000 * (A/P,4%,7) + 1000 + 1000 * (A/G,4%,7)
= 20000 *0.166610 + 1000 + 1000 *2.843318
= 7175.52
EUAC for 8 yrs = 20000 * (A/P,4%,8) + 1000 + 1000 * (A/G,4%,8)
= 20000 *0.148528 + 1000 + 1000 *3.294434
= 7264.99
As EUAC is lowest in 6th yr, Economic life = 6 yrs
6. You’ve been tasked to evaluate an existing piece of machinery.You collected the following data: Today...
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