A 100 W lightbulb generates 97 W of heat, which is dissipated through a glass bulb...
A 100 W lightbulb generates 97 W of heat, which is dissipated through a glass bulb that has a radius of 2.8 cm and is 0.9 mm thick. What is the difference in temperature between the inner and outer surfaces of the glass? In celcius
Homework Answers
We write the expression for temparature difference as
ΔT=Pl/KA = (97W)(0.9*10^-3m) / (0.84J/sm°C) * (4π(2.8*10^-2m)^2) = 10.55 °C
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A 100 W lightbulb generates 97 W of heat, which is dissipated
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