If F(x) = {k=o AkLk (x) Obtain Parsevals Identity Fºe-*[f(x)]?dx = 2 = A That Is
Q. If f(x) = ER=o AxLx(x) obtain Parsevals identity Some *(x)]dx That is
dy If a ER-1} and b ER({1}, the solution of x- dx + a -y= 1-b a +1 -xy' is 1-b Select one: O a. y 1-6 = x+C+xa O b.y = x+C+x2-1 ocyl-6 =C+x-a od y1-b = x+cx-a oe.yB-1 = x+c+xQ O f. y = x+C+x-2 o g. 71-b = x+C O h. y = x+c+x-a
Suppose that l's f(x)dx = 2, Lot f(x)dx = -6 and [ f(a) =1 Compute f(x)dx O 5 O-5 -9 O-4 O9
If a ERI{-1} and b ER{1}, the solution of x- dx + 12 y = at oxy is Select one: o a. y1-b = x + c O b. y b= x+c+x-a O c.y1-b = x+c+xa d. y1 -b = c+x-a e. yb - 1 = x+c+xa f. yi-b = x + cx-a 8. y = x+c+xa y = x+c+x+1 Ni
Given the following table of data: 0.00 0.250.500.751.00 f(x) 0.39890.38670.35210.30110.2420 Estimate f(x) dx Estimate Jo f (Q) dx (i) by composite trapezoidal rule (ii) by Romberg integration of 0(h6), R33
Given the following table of data: 0.00 0.250.500.751.00 f(x) 0.39890.38670.35210.30110.2420 Estimate f(x) dx Estimate Jo f (Q) dx (i) by composite trapezoidal rule (ii) by Romberg integration of 0(h6), R33
some help please
o D. go Given y=f(u) and u = g(x), find dy/dx = f(g(x))g'(x). y = sin u, u = 2x + 12 Select one: A. 2 cos (2x + 12) B. cos (2x + 12) C. - 2 cos (2x + 12) D. - cos (2x + 12)
a dy If a ERI{-1} and b ER\{1}, the solution of x dx + y= a +1 1-b -xyb is 1-b Select one: 1. y-b = x+c+ xa b. yb=1 = x+c+xa O c.y? -b = x + c O d. y1= b = x+cx-a e. y = x+c+x-a O f. y = x+c+xa-1 o g. -b = x+c+x-a 0 h. y1-b = c+x-a
2. Consider the function sx if x EQ, f(x) = { 1-x if x ER\Q. a) Prove that f(x) is discontinuous everywhere except at 1. b) Hence, or otherwise, find a bijection g : [0, 1] → [0, 1] which is discontinuous everywhere in (0,1).
✓ Saved Question 2 (1 point) Given that S3'! f(x) dx = 7, Si f(x) dx = -2, and S31 g(x) dx = 4, which of the following integrals cannot be found? O S3+ f(x) · g(x) dx PS3? (f(x) + g(x)) dx O Si (f(x) + g(x)) dx ° 835 f(x) dx
Evaluate the following integrals. (a) / In(3x) dx for x > 0 (e) / ( +er) dx (n lete* dx (e) sin(5x +1) dx
Suppo ſº swdx = 2. [ f(x) dx = 17. ["f«x) dx = 5. Then x) dx = [ f(x)dx= [ºsw)dx= ]