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QUESTION 18 At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction: 2 ICI(g) = 12(g) + Cl2(g). W
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Answer #1

molarity of I2   = no of moles/volume in L

                       = 3.76/4   = 0.94M

molarity of Cl2   = no of moles/volume in L

                        = 3.76/4   = 0.94M

---------- 2ICl(g) --------------> I2(g) + Cl2(g)

I---------- 0 --------------------0.94----------0.94

C-------- 2x ------------------- -x ---------- -x

E-------- 2x ------------------0.94-x ------ 0.94-x

          Kc   = [I2][Cl2]/[ICl]^2

         0.11   = (0.94-x)(0.94-x)/(2x)^2

         0.11   = (0.94-x/2x)^2

        0.3316   = 0.94-x/2x

      0.3316(2x) = 0.94-x

        x = 0.565

[Cl2]    = 0.94-x = 0.94-0.565   = 0.375M

        0.375 >>>>>answer

       

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