molarity of I2 = no of moles/volume in L
= 3.76/4 = 0.94M
molarity of Cl2 = no of moles/volume in L
= 3.76/4 = 0.94M
---------- 2ICl(g) --------------> I2(g) + Cl2(g)
I---------- 0 --------------------0.94----------0.94
C-------- 2x ------------------- -x ---------- -x
E-------- 2x ------------------0.94-x ------ 0.94-x
Kc = [I2][Cl2]/[ICl]^2
0.11 = (0.94-x)(0.94-x)/(2x)^2
0.11 = (0.94-x/2x)^2
0.3316 = 0.94-x/2x
0.3316(2x) = 0.94-x
x = 0.565
[Cl2] = 0.94-x = 0.94-0.565 = 0.375M
0.375 >>>>>answer
please help QUESTION 18 At a certain temperature the equilibrium constant, Kc, equals 0.11 for the...
termolecular QUESTION 11 At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction: 2 ICl(g) =12(g) + Cl2(g). What is the equilibrium concentration of Cl2 if 2.68 mol of 12 and 2.68 mol of Cl2 are initially mixed in a 3.0-L flask? *Please report 3 significant figures. Numbers only. No unit. No scientific notation QUESTION 12
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