Using ohm's law:
V = i*R
J = i/A
R = rho*L/A
Using above equations:
V = J*A*rho*L/A
rho = V/(J*L)
rho = 147/(2.1*10^4*8.8)
rho = 7.95*10^-4 ohm-m
When 115 V is applied across a wire thatis 11 m long and has a 0.30 mm radius, thecurrent density is 1.3 104 A/m2. Find the resistivityof the wire. 1·m
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When a potential difference of 12 V is applied to a wire 6.6 m long and 0.33 mm in diameter the result is an electric current of 2.0 A . 1. What is the resistivity of the wire?
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