Voltage V = 115 V
Length L =11 m
Radius r= 0.3 mm = 0.3 * 10 ^ -3 m
Current density J = 1.3 * 10 ^ 4 A / m^ 2
Current I = J A
Where A= area = πr ^ 2 = 2.827 * 10 ^ -7 m ^ 2
So, I = 3.675 * 10 ^ -3 A
Resistance R = V / I
= 31286.86 ohm
p=V/(J*L)=115/(1.3e4*11)=8.04e-4
The current density accounts for the resistivity of the
area(note that it's units are Amperes/ meters squared). The only
element that remains is the voltage difference over the distance
(literally and thus mathmatically).
When 115 V is applied across a wire thatis 11 m long and has a 0.30...
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