Dolomite, [CaMg(CO3)2] is found in a soil sample. A geochemist titrates 24.65 g of soil with 57.85 mL of 0.3315M HCl. What is the mass % of dolomite in the soil?
Dolomite, [CaMg(CO3)2] is found in a soil sample. A geochemist titrates 24.65 g of soil with 57.85 mL of 0.3315M HCl. What is the mass % of dolomite in the soil?
2H+ + CO3-2 --> H2CO3
mol of HCl = Macid*Vacid = 57.85*0.3315 = 19.177275 mmol of HCl = 19.177275*10^-3 mol
now,
ratio is 2:!
19.177275 mmol of HCl = 19.177275/2 = 9.5886375 mmol of CO3-2
[CaMg(CO3)2]
1 mol of dolomite = 2 mol fo CO3-2
x mol of dolomit = 9.5886375 mmol of CO2-3
x = 9.5886375 /2 = 4.79431 mmol of dolomite
mmol of CaMg(CO3)2 --> 4.79431
MW of dolmite = 184.40 g/mol
mass of dolomite = (4.79431 *10^-3)(184.40 ) =0.884 g of CaMg(CO3)2
then
% mass = 0.884/24.65*100% = 3.5862%
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