A 7.5 V potential difference is applied between the ends of a 0.70-mm-diameter, 50-cm-longnichrome wire. What...
A 2.0 V potential difference is applied between the ends of a 0.80-mm-diameter, 80-cm-long nichrome wire. Part A What is the current in the wire? Express your answer using two significant figures.
A 8.0 V potential difference is applied between the ends of a 0.80-mm-diameter, 90-cm-long nichrome wire. What is the current in the wire?
A 5.0 V potential difference is applied between the ends of a 0.80-mm-diameter, 85-cm-long nichrome wire. What is the current in the wire? resistivity of nichrome is 1.5*10^-6 (I think, if im wrong use something else)
A6.0V potential difference is applied between the ends of a 0.80-mm-diameter, 40-cm-long nichrome wire. Part A What is the current in the wire?
You apply a potential difference of 4.3 V between the ends of a wire that is 2.2 m in length and 0.662 mm in radius. The resulting current through the wire is 17.6 A. What is the resistivity of the wire? (Give your answer in scientific notation using Ohm.m (Ω.m) as unit)
Part A How long must a 0.70-mm-diameter aluminum wire be to have a 0.46 A current when connected to the terminals of a 1.5 V flashlight battery? Express your answer to two significant figures and include the appropriate units. L = Value Units Submit Request Answer Part B What is the current if the wire is half this length? Express your answer to two significant figures and include the appropriate units. I= Value Units Submit Request Answer
A 5.0 V potential difference is applied between the ends of a 0.60-mm-diameter, 90-cm-long nichrome wire. Part AWhat is the current in the wire? Express your answer in amperes.
1. The terminals of a 0.70 V watch battery are connected by a 130-m-long gold wire with a diameter of 0.100 mm . What is the current in the wire? Express your answer using three significant figures in mA 2. A waterbed heater uses 500 W of power. It is on 35 % of the time, off 65 % .What is the annual cost of electricity at a billing rate of $0.12 per kWhr? Express your answer using two significant...
There is a potential difference of 1.9 V between the ends of a 20 cm long graphite rod that has a cross-sectional area of 1.3 mm^2. The resistivity of graphite is 7.5 x 10^-6 ohm-m. Find the resistance of the rod. Find the current. Find the electric field inside the rod.
The potential difference between the two ends of a conducting wire is 20.0 V and the current through the wire is 4.00A. a) What is the resistance of the wire? b) How much power is being dissipated in the wire?