A 8.0 V potential difference is applied between the ends of a 0.80-mm-diameter, 90-cm-long nichrome wire. What is the current in the wire?
Area
A=pi*D2/4 =pi*(0.8*10-3)2/4 =5.0265*10-4m2
Resistance of the wire is
R=pL/A =(1.5*10-6)(0.9)/(5.0265*10-4)
R=2.68574 ohms
Current flowing in the wire is
I=V/R =8/2.68574
I=2.9787 A
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