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A ray in glass arrives at the glass-water interface at an angle of 48° with the...

A ray in glass arrives at the glass-water interfac

A ray in glass arrives at the glass-water interface at an angle of 48° with the normal. The refracted ray, in water, makes a 72° angle with the normal. The index of refraction of water is 1.33. In Figure 23.2a, the angle of incidence of a different ray in the glass is 37°. The angle of refraction in the water is closest to:

(The answer is already provided. I need to see all appropriate work and make sure that how you derive your answer makes sense.)

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Answer #1

n1sin(48) = n2sin(72)

n1*0.743 = 1.33*0.95

=> nglass = 1.7

againg using it

1.7*sin(37) = 1.33*sin(P)

1.7*0.60 = 1.33sin(P)

=> P OR theta = 49.46 degree

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