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6) Predict missing starting compound and reagent in the following transformations (14 points). a. Robinson annulation...
The following compound undergoes an intramolecular Robinson annulation reaction consisting of a conjugate addition followed by...
The following compound undergoes an intramolecular Robinson annulation reaction consisting of a conjugate addition followed by an aldol condensation. Draw the final product. No mechanism needed. Question 3 ( 5 points ) СН3 HO molargla H3C Create OscerSketch Answer 3 Question 4 Predict the product of the following reaction sequence. Draw the single main product structure only. ( 5 points ) H3C LDA (acid workup) Create OscerSketch Answer 4
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?:...
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?: ONa ONa & Gare A. ONa 29. The Robinson annulation is best described as a(n): A. aldol followed by a conjugate addition B. Michael reaction followed by an aldol C. double aldol followed by an E1cb elimination D. alkylation, then aldol, then a Michael addition 30. Select the product for the reaction shown below: НО. KOH o ? T A. B. C. D.
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?:...
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?: O ONa ONa & التملة ONa A. B. ONa OH C. D. 29. The Robinson annulation is best described as a(n): A. aldol followed by a conjugate addition B. Michael reaction followed by an aldol C. double aldol followed by an E1cb elimination D. alkylation, then aldol, then a Michael addition
Need Help. Will Rate If Complete. 1) NaoEt, EtOH Br 2) O 3) H30+ / A....
Need Help. Will Rate If Complete.
1) NaoEt, EtOH Br 2) O 3) H30+ / A. 1) NaoEt, EtOH (s) ar 2) Y Br 3) Hz0+ / A 1) NaOme/MeOH ~ Br OMe 3) Hz0+/A. 1) NaOEt, EtOH 2) V Br 3) NaOEt, EtOH COOEt 5) H30+/A Robinson Annulation NaoEt, EtOH/A come lui OMe 28- The following molecules can be formed by either: Michael Reaction; Enamine Acylation; Acetoacetic Ester Synthesis; Michael Addition; Malonic Ester Synthesis; Robinson Annulation; Aldol Condensation; Claisen...
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?:...
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?: ONa ONa & Go & ONa A. ONA OH D 29. The Robinson annulation is best described as a[n): A. aldol followed by a conjugale addition B. Michael reaction followed by an aldol C. double aldol followed by an E1cb elimination D. alkylation, then aldol, then a Michael addition
The Robinson annulation is a classic example of what could be considered a paired reaction - that...
please complete number 1 and 2 COMPLETELY
The Robinson annulation is a classic example of what could be considered a paired reaction - that is a reaction that is made up of a sequence of two simpler reactions. In the case of the Robinson annulation, it is a Michael Addition followed by an intramolecular aldol. For the following Robinson annulation, go through the mechanism of the initial Michael addition and then look at how many different intramolecular aldol reactions could...
1. The Robinson annulation is a classic example of what could be considered a paired reaction-...
1. The Robinson annulation is a classic example of what could be considered a paired reaction- that is a reaction that is made up of a sequence of two simpler reactions. In the case of the Robinson annulation, it is a Michael Addition followed by an intramolecular aldol. For the following Robinson annulation, go through the mechanism of the initial Michael addition and then look at how many different intramolecular aldol reactions could happen. Analyze each one in terms of...
1. A Robinson annulation is a reaction that involves: (i) a Michael addition of an enolate...
1. A Robinson annulation is a reaction that involves: (i) a Michael addition of an enolate onto an ,ß-unsaturated enone followed by (ii) an intramolecular aldol reaction. The molecule shown below (cyclohexenone X) can be made through two different Robinson annulation reactions. (A) Show the two different sets of starting materials (i.e. ketone 1 &a,p-unsaturated enone 1 and ketone 2 & a,B-unsaturated enone 2) for each Robinson annulation. Draw the reagents/reaction conditions. (B) Then pick one set and draw an...
5. Predict the product of the Robinson Annulation. sigue KOH, H20, heat 6. Predict the major...
5. Predict the product of the Robinson Annulation. sigue KOH, H20, heat 6. Predict the major organic products. 1. LIAIHA 2. H+ CH3CH2CH.SK 1. CH3CH_MgBr 2. H+ CH3CH2OH (CH2CH)Culi KCN H20 7. Predict the two possible products of the intramolecular Aldol condensation. chlo KOH, H20, heat
(2) Retrosynthesis. Provide the starting materials needed to yield the following products through either an aldol...
(2) Retrosynthesis. Provide the starting materials needed to yield the following products through either an aldol reaction/condensation, a Michael addition, or a Robinson annulation. If a specific base must be used to aid selectivity of any step, please specify. (20 pts)
The following compound undergoes an intramolecular Robinson annulation reaction consisting of a conjugate addition followed by an aldol condensation. Draw the final product. No mechanism needed. Question 3 ( 5 points ) СН3 HO molargla H3C Create OscerSketch Answer 3 Question 4 Predict the product of the following reaction sequence. Draw the single main product structure only. ( 5 points ) H3C LDA (acid workup) Create OscerSketch Answer 4
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?: ONa ONa & Gare A. ONa 29. The Robinson annulation is best described as a(n): A. aldol followed by a conjugate addition B. Michael reaction followed by an aldol C. double aldol followed by an E1cb elimination D. alkylation, then aldol, then a Michael addition 30. Select the product for the reaction shown below: НО. KOH o ? T A. B. C. D.
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?: O ONa ONa & التملة ONa A. B. ONa OH C. D. 29. The Robinson annulation is best described as a(n): A. aldol followed by a conjugate addition B. Michael reaction followed by an aldol C. double aldol followed by an E1cb elimination D. alkylation, then aldol, then a Michael addition
Need Help. Will Rate If Complete.
1) NaoEt, EtOH Br 2) O 3) H30+ / A. 1) NaoEt, EtOH (s) ar 2) Y Br 3) Hz0+ / A 1) NaOme/MeOH ~ Br OMe 3) Hz0+/A. 1) NaOEt, EtOH 2) V Br 3) NaOEt, EtOH COOEt 5) H30+/A Robinson Annulation NaoEt, EtOH/A come lui OMe 28- The following molecules can be formed by either: Michael Reaction; Enamine Acylation; Acetoacetic Ester Synthesis; Michael Addition; Malonic Ester Synthesis; Robinson Annulation; Aldol Condensation; Claisen...
28. Which intermediate is not on the mechanistic pathway directly leading to the Robinson annulation product?: ONa ONa & Go & ONa A. ONA OH D 29. The Robinson annulation is best described as a[n): A. aldol followed by a conjugale addition B. Michael reaction followed by an aldol C. double aldol followed by an E1cb elimination D. alkylation, then aldol, then a Michael addition
please complete number 1 and 2 COMPLETELY
The Robinson annulation is a classic example of what could be considered a paired reaction - that is a reaction that is made up of a sequence of two simpler reactions. In the case of the Robinson annulation, it is a Michael Addition followed by an intramolecular aldol. For the following Robinson annulation, go through the mechanism of the initial Michael addition and then look at how many different intramolecular aldol reactions could...
1. The Robinson annulation is a classic example of what could be considered a paired reaction- that is a reaction that is made up of a sequence of two simpler reactions. In the case of the Robinson annulation, it is a Michael Addition followed by an intramolecular aldol. For the following Robinson annulation, go through the mechanism of the initial Michael addition and then look at how many different intramolecular aldol reactions could happen. Analyze each one in terms of...
1. A Robinson annulation is a reaction that involves: (i) a Michael addition of an enolate onto an ,ß-unsaturated enone followed by (ii) an intramolecular aldol reaction. The molecule shown below (cyclohexenone X) can be made through two different Robinson annulation reactions. (A) Show the two different sets of starting materials (i.e. ketone 1 &a,p-unsaturated enone 1 and ketone 2 & a,B-unsaturated enone 2) for each Robinson annulation. Draw the reagents/reaction conditions. (B) Then pick one set and draw an...
5. Predict the product of the Robinson Annulation. sigue KOH, H20, heat 6. Predict the major organic products. 1. LIAIHA 2. H+ CH3CH2CH.SK 1. CH3CH_MgBr 2. H+ CH3CH2OH (CH2CH)Culi KCN H20 7. Predict the two possible products of the intramolecular Aldol condensation. chlo KOH, H20, heat
(2) Retrosynthesis. Provide the starting materials needed to yield the following products through either an aldol reaction/condensation, a Michael addition, or a Robinson annulation. If a specific base must be used to aid selectivity of any step, please specify. (20 pts)
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