Question

please show each law for each step when working out the question. please do not skip and steps and one law per line please and state every line even if it is the same law please. Show that ¬(?∧(?∨¬¬?))≡¬?

i need to answer like this format. i have tried many times, but the questions are random.
• You can enter formulas using either the operations 7,1,V, or English words not, and, or. So, the input "p and (q or not p)" is the same as "pA • At the bottom of this question you will find a table with the list of operations, and the keywords to use. Entering your solution Please note that the system should accept any correct answers, but it is very strict about it: you can only apply one law per step, not more (note t also includes the fact that you cannot apply the same law twice in one go - it has to be done in two steps: it is one law per step, not one type of la step). The checker should tell you when it thinks that you entered more than one law. It is not possible to reveal the solution: checking the solution automatically is easier than computing the solution. You may copy-paste the expression in the first box:-(pA (p V9)) Select the number of steps you need: LHS = -(p^ (p V --q)) -(p ^ (p V 779)) (p ^ (p v q)) (p ^ (p V q)) Distributive Law Brooklyn.Ni....torrent

Answer 1

$\color{red}LHS=\lnot(p\land(p\lor\lnot \lnot q))\equiv\lnot(p\land(p\lor q)$ (by Law of double negation: $\lnot \lnot q=q$ )

  

= p V-VO

(by De-Morgan's law: )

be Ad = (b yd)

$\color{red}\equiv \lnot p\lor (\lnot p\land\lnot q)$

(by De-Morgan's law:$\lnot (p\lor q)\equiv \lnot p\land\lnot q$)

$\color{red}\equiv \lnot p$

(by Absorption law: $p\lor(p\land q)\equiv p$ )