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Topic: Organic Chemistry

Please provide step by step solutions to each problem along with a brief explanation as to why you picked your answer.

To whoever helps me, please know that I am stuggeling so hard with this class. I'm not smart like everyone else, so please (if you can) be detailed and if you have time, please try to explain to me why you did what you did. I just don't get this subject, it seems so random and people skip so many steps so I cannot follow. Please help. Thank you so much.

2. Provide the best systematic name for each of the following alkenes a. b. C.

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Answer #1

(E)-3-ethylhexa-1,4-diene Explanation: since compound has two double bond the name ends with diene we should find the longest carbon chain which has 6 carbons the numbers are denoted in the structure, therefore the basic name hexa-1.4-diene we should number in such a way the doublebond get least number, therefore number starts with terminal double bond 3rd position has ethyl group therefore complete name 3-ethylhexa-1,4-diene nc st 1st H 2nd to assign double bond configuration we want rank the substitutent of the double bond based on the atomic number of the attached atom therefore methyl get 1st rank and hydrogen get 2nd rank, similarly in other side carbon substitutent get first rank and hydrogen get second rank. in above ranking 1st rank substitutent is opposite eachother and 2nd rank substitutent is opposite to eachother therefore double bond configuration is E the complete name is (E)-3-ethylhexa-1,4-diene 6-methylocta-2,4-diene Explanation: since compound has two double bond the name ends with diene we should find the longest carbon chain which has 8 carbons the numbers are denoted in the structure, therefore the basic name octa-1.4-diene we should number in such a way the doublebond get least number 6th position has methyl group therefore complete name 6-methylocta-2.4-diene

therefore the complete name for compound b is 2E,4E-6-methylocta-2,4-diene.

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