Question

An old piece of wood's coal's mass is 118g and activity 11 Bq. How old is the piece? Out of natural coal, the radioactive part is f = 1.3 * 10^-12 and its half-life is 5730 years. A year has on average 3.156 * 10^7 seconds. Give your answer in years.

Answer 1

Amount of wood's coal's = 1189m. Half life of the radio alline element the 5730 yes. 25730x 3.156 x 107 se teve deery Contat 22 0.693 - tv2 2 0.693 sul 5730x3 156 0107 on present at any infort NE- No e-xt - Nta endt s – ate in (NH) 7 Ata mlo Non 1 & t= ln (NW ) The No. & atom.. presen No Mt 6 1.341512 av ore 1012 her 182 1.3] (10) - (21.3) 7 year 0.697 5730 o 12 th 10- 1413) 5730 72 693 L 2 8 268 x 27.4 year. z 22 6 5 4 3 year Z yean.) z 2-3010 Canned c anner It