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12 500nm light incident from air (Nair = 1.00) Strikes a thin film of oil (noil...
A thin film of olive oil (index of refraction noil = 1.46) of thickness d is...
A thin film of olive oil (index of refraction noil = 1.46) of thickness d is floating on the surface of still water (index of refraction nwater = 1.33). The index of refraction of air is nair = 1.00. A red laser of wavelength λ=600nm=6.00×10−7m is incident on the film of olive oil from above as shown. The laser reflects at the air-oil and oil-water interfaces and interferes with itself. Answer the following questions: 1. What does the thickness d...
A thin film of olive oil (index of refraction noil = 1.46) of thickness d is...
A thin film of olive oil (index of refraction
noil = 1.46) of thickness d is
floating on the surface of still water (index of refraction
nwater = 1.33). The index of refraction of air
is nair = 1.00.
A red laser of wavelength
λ=600nm=6.00×10−7m is incident on the film of olive oil from above
as shown. The laser reflects at the air-oil and oil-water
interfaces and interferes with itself.
Answer the following questions:
1. What does the thickness d...
A light ray in air (n= 1) is incident on a thin film of oil (noil...
A light ray in air (n= 1) is incident on a thin film of oil (noil = 1.60) floating on top of water (nwater = 1.33), as shown below. The wavelength of the incident light in air is Aair = 640 nm. The oil layer has a thickness t = 0.5 um. The ray is assumed to be incident practically along the normal. That is, we won't be worried about angles of reflection or refraction when doing this problem. However,...
6) A ray of light traveling in air (nair = 1.0) is incident on a film...
6) A ray of light traveling in air (nair = 1.0) is incident on a film of oil, making an angle of incidence of 47°, as shown. When the ray refracts into the oil, it makes an angle of 31°, as shown. After traveling through the oil, the ray is then incident on water (nwater = 1.33). (7 points) Determine the index of refraction of the oil, noit 470 Air Oil Water (8 points) Determine the angle A that the...
Wave Optics CHAPTER 17 17-5 17.4 Thin-Film Interference oure shows a wave transmitted from air through...
Wave Optics CHAPTER 17 17-5 17.4 Thin-Film Interference oure shows a wave transmitted from air through a thin oil film on water. The film has a kness t oil/2, where Noil is the wavelength of the light while in the oil. 2. The fi nicna n1 1.00 n2 1403 1.33 a. Referring to the indices of refraction shown on the figure, indicate at each boundary with a Y (yes) or N (no) whether the reflected wave undergoes a phase change...
light of wavelength in air is ? in air is incident on a thin film of...
light of wavelength in air is ? in air is incident on a thin
film of refractive index n=1.5 whose thickness varies with height.
the interference pattern observed from the left hand side of the
film is shown in the diagram. by what amount does the film
thickness change between points A and B?
1.33? 2? 2.66? 3? 4?
What is the critical angle for light incident on water water = 1.33 from air nair...
What is the critical angle for light incident on water water = 1.33 from air nair = 1.00 for total internal reflection? Answer:
A ray of light traveling in air (????=1.0) is incident on a film of oil, making...
A ray of light traveling in air (????=1.0) is incident on a film
of oil, making an angle of incidence of 47°, as shown. When the ray
refracts into the oil, it makes an angle of 31°, as shown. After
traveling through the oil, the ray is then incident on water
(??????=1.33).
A) Determine the index of refraction of the oil, ????.
B) Determine the angle ?? that the ray makes as it travels
through the water.
470 Air 31....
please answer asap and use Nair=1 Nwater=1.333 and c=3x10^8 m/s 4) Fig. 4 A light ray...
please answer asap and use Nair=1 Nwater=1.333 and c=3x10^8
m/s
4) Fig. 4 A light ray in water of wavelength 529nm is incident on flat, rectangular piece of transparent plastic (n 1.49) that is floating on a pool of water (n= 1.333). The ray from the water strikes the bottom of the plastic at an angle of 40.0° from the normal line. What happens to the ray when it hits the top edge of the plastic? (give all numeric quantities)...
A thin layer of oil with index of refraction no = 1.47 is floating above the...
A thin layer of oil with index of refraction no = 1.47 is floating above the water. The index of refraction of water is nw = 1.3. The index of refraction of air is na = 1. A light with wavelength 1 = 750 nm goes in from the air to oil and water. n n (a) Express the wavelength of the light in the oil. 1o, in terms of 1 and no- (b) Express the minimum thickness of the...
A thin film of olive oil (index of refraction
noil = 1.46) of thickness d is
floating on the surface of still water (index of refraction
nwater = 1.33). The index of refraction of air
is nair = 1.00.
A red laser of wavelength
λ=600nm=6.00×10−7m is incident on the film of olive oil from above
as shown. The laser reflects at the air-oil and oil-water
interfaces and interferes with itself.
Answer the following questions:
1. What does the thickness d...
A light ray in air (n= 1) is incident on a thin film of oil (noil = 1.60) floating on top of water (nwater = 1.33), as shown below. The wavelength of the incident light in air is Aair = 640 nm. The oil layer has a thickness t = 0.5 um. The ray is assumed to be incident practically along the normal. That is, we won't be worried about angles of reflection or refraction when doing this problem. However,...
6) A ray of light traveling in air (nair = 1.0) is incident on a film of oil, making an angle of incidence of 47°, as shown. When the ray refracts into the oil, it makes an angle of 31°, as shown. After traveling through the oil, the ray is then incident on water (nwater = 1.33). (7 points) Determine the index of refraction of the oil, noit 470 Air Oil Water (8 points) Determine the angle A that the...
Wave Optics CHAPTER 17 17-5 17.4 Thin-Film Interference oure shows a wave transmitted from air through a thin oil film on water. The film has a kness t oil/2, where Noil is the wavelength of the light while in the oil. 2. The fi nicna n1 1.00 n2 1403 1.33 a. Referring to the indices of refraction shown on the figure, indicate at each boundary with a Y (yes) or N (no) whether the reflected wave undergoes a phase change...
light of wavelength in air is ? in air is incident on a thin
film of refractive index n=1.5 whose thickness varies with height.
the interference pattern observed from the left hand side of the
film is shown in the diagram. by what amount does the film
thickness change between points A and B?
1.33? 2? 2.66? 3? 4?
What is the critical angle for light incident on water water = 1.33 from air nair = 1.00 for total internal reflection? Answer:
A ray of light traveling in air (????=1.0) is incident on a film
of oil, making an angle of incidence of 47°, as shown. When the ray
refracts into the oil, it makes an angle of 31°, as shown. After
traveling through the oil, the ray is then incident on water
(??????=1.33).
A) Determine the index of refraction of the oil, ????.
B) Determine the angle ?? that the ray makes as it travels
through the water.
470 Air 31....
please answer asap and use Nair=1 Nwater=1.333 and c=3x10^8
m/s
4) Fig. 4 A light ray in water of wavelength 529nm is incident on flat, rectangular piece of transparent plastic (n 1.49) that is floating on a pool of water (n= 1.333). The ray from the water strikes the bottom of the plastic at an angle of 40.0° from the normal line. What happens to the ray when it hits the top edge of the plastic? (give all numeric quantities)...
A thin layer of oil with index of refraction no = 1.47 is floating above the water. The index of refraction of water is nw = 1.3. The index of refraction of air is na = 1. A light with wavelength 1 = 750 nm goes in from the air to oil and water. n n (a) Express the wavelength of the light in the oil. 1o, in terms of 1 and no- (b) Express the minimum thickness of the...
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