Block B has a mass of 3.60kg and is moving to the left at a speed of 3.80m/s. Block A has a mass of 7.20kg and is moving to the right. The two blocks undergo a perfectly inelastic collision. What should be the velocity of Block A in order to have the two blocks remain at rest after the collision?
m1 = 3.6 kg, u1 = -3.8 m/s, m2 = 7.2 kg, v = 0
for inelastic collision
from conservaiton of momentum
m1u1 +m2u2 = (m1+m2)v
3.6*-3.8 +7.2*u2 = (3.6+7.2)*0
u2 = 1.9 m/s
Block B has a mass of 3.60kg and is moving to the left at a speed...
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A block of mass m1 = 1.60kg moving at v1 =
2.00m/s undergoes a completely inelastic collision with a stationary
block of mass m2 = 0.100kg . The blocks then move, stuck
together, at speed v2. After a short time, the two-block
system collides inelastically with a third block, of massm3 = 2.70kg , which is initially at rest. The three blocks
then move, stuck together, with speed v3.(Figure 1) Assume that the
blocks slide without friction.Part AFind v2v1, the...