Resolving Distant Objects
Part AIf two point sources of light are beingimaged by this telescope, what is the maximum wavelength
Part B
to see the applet copy and paste the link below in brouser
http://mp.pearsoncmg.com/probhtml/applets/resolve.html
In thisapplet, change the settings to match the situation in PartA. Notice how the diffraction pattern looks when the two sourcesare at the resolution limit(i.e., just resolved). Now change thewavelength to 650 nanometers and the aperture diameter to 1.5centimeters. Use the applet to roughly determine at whatangularseparation the two points are just resolved.
Express your answer in radians to two significant figures.5.3×10−5
Part C
Calculate the angular separation
PLEASE NEED HELP JUST WITH PART C
thanks
Homework Answers
θ is the angularresolution,
- λ is the wavelength of light,
- and D is the diameter of the lens' aperture.
- from the above relation we can solve for wavelength.
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Part D What is the angular radius 0 of the first dark ring for a point source being imaged by this telescope? Use 550 nanometers for the wavelength,since this s near the average for visible light Express your answer in degrees, to three significant figures 197 ΑΣφ Request Answer Diftraction due to a circular aperture is important in astronomy Since a tolescopo has a circular aporture of finite size, stars are not imagod as points, but rathor as iftraction patterns....
Learning Goal: To use the formulas for the locations of the dark bands and understand Rayleigh's criterion of resolvability.An important diffraction pattern in many situations is diffraction from a circular aperture. A circular aperture is relatively easy to make: all that you needis a pin and something opaque to poke the pin through. The figure shows a typical pattern. It consists of a bright central disk, called the Airy disk,surrounded by concentric rings of dark and light.While the mathematics required...
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