Question

(10%) Problem 13: A particle of mass 0.15 kg moves along the x-axis with a potential energy whose dependence on x is shown in the figure. U(X)(J) 4 12.07 .. 4.07 4.0 8.0 12.0 16.0 20.0 x(m) -4.07 -8.07 -12.07 25% Part (a) What is the force in the x-direction, in newtons, on this particle at x = 8.0 m? Grade Summary Deductions 0% Potential 100% π HOME sino cos tan cotan asin() acos atan acotan) sinh cosh) tanho cotanh() Degrees Radians Submissions Attempts remaining: 5 (2% per attempt) detailed view 3 ^! 4 5 1 2 0 Vol BACKSPACE IND CLEAR Hint Submit Hints: 1% deduction per hint. Hints remaining: 1 F eedback I give up! Feedback: 0% deduction per feedback. A 25% Part (b) If the total mechanical energy of the particle is -6.0 J, what is the minimum position the particle can have? 25% Part (c) If the total mechanical energy of the particle is -6.0 J, what is the maximum position the particle can have? A 25% Part (d) If the total energy is 16.5 J, what is the speed of the particle at x = 8.0 m?

Answer 1

Salutim: - m = 0.15 kg at n=8m - potential energy is straight line in the region 6m to com : the force on a particle in this region is negative of the slope of the line. Fagott - du =-612-127 J (10-6m i F = GNI 6 Here the mechanical energy line cuts the potential energy Curve from the graph minimum position the particle = am manimum position the particle = 15m € The total energy is 16.5 t KE = Total mehanical energy - potential energy K.E 16.5-0 -165J ₂ mv2 = 16.5 => + (0.15) v² = 16.5 V? - 16.5%0,075 > V 220 -V Iv=14.832 mis)

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