Question

^{Consider a mixture of neon (Ne, MW = 20.18 g/mol) and krypton (Kr, MW = 83.80 g/mol) at a temperature T = 309.15 Kelvin. The total pressure of the gas mixture is p = 811.4 torr, and the density of the gas mixture is 2.556 g/L. Find the following.
a) The volume occupied by 1.000 moles of the gas mixture.
b) p(Ne), the partial pressure of neon gas in the gas mixture.
For the conditions in the problem you may assume the ideal gas law applies}

The problem is not incomplete.

Answer 1

(6) Total volume of the mintune v= 23.762 Density of mintune f = 2.556 9/1 - mass mass of mixture = fxr. -) Momin = 2.556 g/L X 2 3.762 - Manix = 60.731 g let We be the no of mole of Ne and on to be the no bot mole of Krypton in the mixture given that more t o = 1 mole Now Menin- mex 20.18% moletket 83.8 g/mol -) 60.7319 - Once *20.1897 melet C1- Once] 83.89fmos - 60.7319 - Wex 20.189000 le 183:89-met 83.8 g/mol 83.89-60.7319 = More 783-89% mote het 20.189 - 23.069 g - Sorex 63 62 g/mole. - we = 23.069 g = 0.363 mole. Prev = ve RT-) Pre We RT db -0.363 ono lex 0.0831atom.Lomoek 1x 309.15%, - 0.388 aton. -0-388 x 760 ) town - 294.88towe (onswers ~ 294.9 tonne conswer) 63.62 mole V 23 764