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Two moles of NH3 were placed in a 500.0-mL container at 650°C. At equilibrium, only 71.0%...

Two moles of NH3 were placed in a 500.0-mL container at 650°C. At equilibrium, only 71.0% of the original NH3 was found. Determine the equilibrium constant of the following reaction.              

2 NH3 (g) <--> N2 (g)        +        3 H2 (g)                                    

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Answer #1

> N2 (9) +372 INM₂ (9) Q Initial Now, As 80 71% of original NM3 left at equilinsian 9991. of N ha dissoucity le 8x29 you- ² 0

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