Question

need hep with these two questions!

K2Cr₂O + H₂ C₂04 2H2O sklor (C204) [H202₂/2 H2otca 2k12 2 cr=x2 (+8ly kzcrgo7+ I 142 C204-21420 2 k cellow). (1) 2 - 2 H2O toc -=S7 30-4521 2. Calculate the theoretical yield of K[Cr(C,0.),(H,0), 2H,0. 3. What is the theoretical percentage by weight of Cr in K[Cr(C,0.),(H,0), 2H,0?

here is the information for the lab

Answer 1

Question o Preparab'on of Potathium dioxalatodicquo chromahe (un) dihydrate Balance equation ! Kylacy 09 al _ + 9H, C904.624,0 = iman QK [Cv(6904),(H20), ). 24,0 +6602 aw + 3H20 d According to balanced equabon, mere kg CO On reacts with y maes o oxalic acid to gine too mode of potassium dioxalatodiagnoch romane (11) dinydrate weight of Koco, 07 taken' z oq- Moldoutor weight of kecoon = 294.18591 mol mdes of Ky for boys a mol 7894018528 = 6.798 x10 -Pol

weight. H2 G04,2H30 taken ? Moras weight atau = 26.0654gmolt moles of M₂ CO₂ 12H, O = 126.0654 6 mol 4.759 x 10-2 since, none of them is limiting reagent, we can calculate ambunt of k[Cr (Gou)₂CH. 02], 2tho wring any of the reactant Lig lendles of Kg CG Dm pines & moles of x [coceau) (4,02,2.240 , 6,739 x % sleo 4 4 8 x 6.1983 19holes • Mees of a coc Bag (4,0),240 = 2X 6.798x10?mo Molar man of - 33919,9 mole! weight of " = Moves x (molar weight) =TQX6,798 x 10 9 x (334. 192]g = 4.6 12 g Theoretical yield g k[cofcouz{ 4,077.246,03406129