Consider a long, cylindrical charge distribution of radius R with a uniform charge density ?. Find the electric field at distance r from the axis, where r < R. (Use any variable or symbol stated above along with the following as necessary: ?0.)
The charge inside the cylinder is equal to the charge
distribution times its volume ?V = q_inside. The Electric Flux
through any closed Gaussian surface is equal to the integral of EdA
= EA = q_inside / ?0.
Where the area is the area of the surface of the cylinder with
radius r, perpendicular to the axis = 2*pi*r*l (l = length of
cylinder). and the volume is that of the cylinder of radius r =
pi*(r^2)*l. Substituting and doing the algebra to isolate E gives
you E = (?*pi*(r^2)*l)/(?0*2*pi*r*l). You can do the
simplifications and crossings out :)
Consider a long, cylindrical charge distribution of radius R with a uniform charge density ?. Find...
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stete the answer clearly please
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