Question

The biodiesel formation reaction is carried out in a plug flow reactor. Oil is fed at a flowrate of 10 mol/s. Methanol is fed at a flowrate of 30 mol/s. Determine the volume of the reactor required for a conversion of 95%. Assume that the reaction is irreversible and the reaction is first order with respect to both oil and methanol. Assume that the density of the mixture stays constant along the reactor as 5000 mol/m³. The rate constant for this reaction is 1 m³/(mol.s). The design equation for a plug flow reactor is r_A=dF_A/dV. State all your assumptions.

Answer 1

Solo Above reaction can be Oil & Metharol - described as following. Biodiesel. Giver Oil te Oil feed rate = 10 mol/sec Methand feed rate = 20 mol/sec. Since its first Order reaction with respect to both oil and methanol Oll is a limiting reagent 2 10 moles of all will react with 10 moles of methanol to produce 10 moles of Biodiesel. - Considering oil as a limiting substrate the calculations are done. - For 95 %- conversion: means 95% of reactants have consumed, only 5% reactants. one left. - moles of oil loft = 5 x 10 = 0.5 Moles of methanol left = 5 x 10 = 0.5+20= 2005 [Out of 30 moles, 20 moles are left unreacted while 95% of 10 moles are reacted] since it is first order reaction, that moms 95% of biodiesel is produced. - Oil Methanol Biodiesel: Total moles in the reactor = 0.sto5 +20 Cunreacted) 9.5 = 30.5 moli Density at mixture remains constant = 5000 mo/m3, lotar moles - Total moles 305 x 1000 L = bolti Density 5000 100 volume of reactor =