Question

An acid-catalyzed irreversible liquid-phase reaction A B is carried out adiabatically in a CSTR. The reaction is second order in A. The feed is equimolar A and solvent (S, which contains catalyst), and enters the reactor at a total volumetric flow rate of 10 dm3/min at a concentration of A of 4 mol/L. The feed enters at 300 K. The product and reactant heat capacities are 15 cal/(mol°C), the solvent is 18 cal/(mol°C). The reaction rate constant at 300 K is 0.0005 dm3/(molmin). The reaction has an activation energy of 15,000 cal/mol and a heat of reaction of -3300 cal/mol/°C. (a) What VCSTR is needed to achieve 80% conversion, and at what temperature does it operate? (b) What conversion can be achieved in a 103 dm3 CSTR, and what is the new exit temperature?

Answer 1

we need to consider the temperature effect on the reaction as the reactor is adiabatic. Go through the explanation.

CAO (Initial concentrofm o A). 4 Cs: (Sodvent cocentatin) kt Cluner tlos rate of feed feed Teup 3oD K and fAo C 15 Cal and -8 -33o YA = A, 8,S A, S adiabatie reactor 300K T2 enugy balance Cps T falpe) (Eno pn Tr fse Gps Ti)- Cfn Ga Tr t Co.2xux1oxIS T2 t 4とDr18 Ta + 0-8r4x1oX15 x た】 4x1ox0.8x (-3300) (4* 10x 15X 3 o t 4x10X18x300) 1320 T2 501600 380 K T7 CrolA A Y (-YA 2 2 R/NA Poy T Vo (1+ Ea XA To

tw hase for Ren and PE PO Vo V. /380 300 NA = NAO (I-XA R/NAo(-XA) 2 300 CAo (1-X No 380 300 2- xO.0005 0.0002 (4-) 380 lOx4 x o.8. 160 o00 t .O002 ante by secing thi tue Reacim Rat Low ( Do nst VHewe be cause Yeactor Lonstant fsalps Ti) - (faspat fGps + fe Cps) T 4x10X830) (4rox -A)XIS 4xlox 18 + 4x1OX XAXIS) T5 4p1D x KAX -3300) (6o0f-XA)T720 +600z) T, (4210x151300 2/b oro 180 0o0 -13 2000 ZA 1320 T 396000 avd (3+XA) T2 10x4 x ZA V= VoCAo 2LA (-A) o3 2.575 LA

2,575 A Ca ICA1-4) 3ao2 vo2 T LA 2.575 X o.0512o A 1854 T CL-XA Piut d rom th valu epu( aud Calaubt &+24)r| 1854 ZA 2.0 538子 r1o 3oD + 1 ISDD X 2,05887-*10"7 K. 3 60D. 20588 7 1vey dos das value A valu of tuge becaue lt vey mor aun