Question

21) The following reaction: 4NH3 +502 + 4NO + 6H20 Is carried out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27 °C, and the volumetric flow rate is 2 dm /s and Cao = 0.1 mol/dm. Calculate the CSTR volume necessary to achieve 85% conversion. Additional Information -41 kcal/mol HR (273) --20 kcal/mol. H (273) -- 15 kcal/mol. HE (273) C = = 15 cal/mol K C = 30 cal/mol K k = 0.01 m. at 300 K E = 10,000 cal/mol

Answer 1

PLEASE LIKE THE ANSWER AND COMMENT FOR FURTHER DOUBTS. THANK YOU.

Performance equation for CSTR ise - KA FAO CAO YA Where v: Volume of reactor, FA = Molar Flow rate, C = Space time i.e. time required to process the batch of reactant creo or (time, CAo is initial concentration of reactants. KA= conversion 1 1M= lo el decimeter or dm .. Im3= 10t3 dm3 k= 0.01 dm x 1.m3 = 1x10m3 mollos lot3 dow molles (time) karate constant (concentration) n = order of reaction. Put n=2 K: ( molt cses). Conta . The order considered in example is second orden Now Vo volumetric flow: 2 dm² - 2 m² = 2x10 3 m3 see 10+3 sec sea e can too. I mal lo dm = 100 mol/ma dm? I mi e o put everything in performance egn e C = X -pp: kA² v HA V = 0.85 KRA. (1-4A) - VCAO -- 2x10 3100 K[CAO (1-4A)]² Equimolar v 0 .87 Feedot 1x103 [100 (1-ogs)] ² CACBO N = 0.858o.R -0.755 m3 0.225 = 755 litres 0.2 Here additional information will not be required