Q1 a) Use the following data to find the velocity and acceleration at t=10 seconds: Time,...
Q1
a)
Use the following data to find the velocity and acceleration at t=10 seconds:
|
Time, t, s 0 |
2 |
4 |
6 |
8 |
10 |
12 |
14 |
16 |
|
Position, x, m 0 |
1.7 |
2.8 |
4.3 |
5.5 |
6.4 |
7.5 |
8.1 |
8.4 |
|
Show proper working with each and every step |
||||||||
b) The velocity “v” of a particle at distance “s” from a point on its linear path is given in the following data
s(m) 0 2.5 5.0 7.5 10.0 12.5 15.0 17.5 20.0 v(m/sec) 16 19 21 22 20 17 13 11 9
(show proper working with each and every step)
Homework Answers
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Q1
a)
Use the following data to find the
velocity and acceleration at t=10 seconds:
Time,...
(a) Use the following data to find the velocity and acceleration at t = 10 seconds:
Numerical methods(a) Use the following data to find the velocity and acceleration at t = 10 seconds:Time (s):0246810121416Position (m):00.71.83.45.16.37.38.08.4Use second-order correct (i) centered finite-difference, and (ii) backward finite-difference methods. (b) Use the Taylor expansions for f(x +h), f(x+2h), f(x +3h) and derive the following forward finite-difference formulas for the second derivative. Write down the error term$$ f^{\prime \prime}(x) \approx \frac{-f(x+3 h)+4 f(x+2 h)-5 f(x+h)+2 f(x)}{h^{2}} $$
13. Find the magnitudes of the initial (at t 0) velocity and acceleration of the auto...
13. Find the magnitudes of the initial (at t 0) velocity and acceleration of the auto respectively At time t 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by -0.50t, in m/s2 for t in seconds 14. Find the time when it stops 15. Find the distance it has traveled tt the end of 4.0 s 16. Find the distance it has traveled by the time it stops
The data on the below shows the number of hours a particular drug is in the...
The data on the below shows the number of hours a particular drug is in the system of 200 females. Develop a histogram of this data according to the following intervals: Follow the directions. Test the hypothesis that these data are distributed exponentially. Determine the test statistic. Round to two decimal places. (sort the data first) [0, 3) [3, 6) [6, 9) [9, 12) [12, 18) [18, 24) [24, infinity) 34.7 11.8 10 7.8 2.8 20 9.8 20.4 1.2 7.2...
QUESTION 1 The following velocity vs time data is given. To find polynomial interpolation are the...
QUESTION 1 The following velocity vs time data is given. To find polynomial interpolation are the velocity at t-14.9s, the three time data points you would choose for second order ime (s Velocity (m/s) 22 O 0. 15, 18 O 15, 18, 22 O o. 15, 22 O 0, 18, 24 15 18 37 25 123 QUESTION 2 The data of velocity vs time is given. 15 18 36 24 Velocity(m/s) 23 5 The velocity in m/s att-16s using linear...
First you need to find the acceleration and then the time Please explain how you get...
First you need to find the acceleration and then the time Please
explain how you get ( t ), which way you have used?. And why.
For
this I only have one question. Do we need to divide the distance r
1 cm by 100 to convert it to m in order to get the final answer? Or
just keep it as its.
Show all work clearly. No credit for answer only. Provide the proper units. 1. A particle of...
The wind data of a site is listed in the attached file. The data summarizes the wind speeds and t...
The wind data of a site is listed in the attached file. The data summarizes the wind speeds and their frequencies at the hub height of the turbine described below. Select a generator size that maximizes the annual energy output. Consider generator ratings in increments of 25 kw. Express the final answer in kWh. Parameters Turbine rotor diameter: 70.0 m Overall efficiency: air density low speeds: 33% 1.16 kg/m generator disengaged for the input values below 30% Site Generator cutoff...
The following data of the velocity of a body as a function of Time (s) Velocity...
The following data of the velocity of a body as a function of Time (s) Velocity (m/s) 22 Using quadratic interpolation, the interpolant time is given as f 24 123 4. 15 24 18 37 25 v(t) 9.500r2 -383.0t +3853 approximates the velocity of the body between 18 and 24 seconds. From $ information, can you find out when the velocity of the body is 26 m/sdurintg above time interval?
An object of weight 1 N is falling vertically. The time vs. speed data can be...
An object of weight 1 N is falling vertically. The time vs. speed data can be found here. In this case the effect of air-drag cannot be neglected. Use your critical thinking to estimate the air-drag coefficient . Make sure you include the units in your answer. 0 0 0.1 0.9992 0.2 1.993 0.3 2.978 0.4 3.948 0.5 4.898 0.6 5.826 0.7 6.728 0.8 7.599 0.9 8.438 1 9.242 1.1 10.01 1.2 10.74 1.3 11.43 1.4 12.09 1.5 12.7 1.6 ...
4. Use the velocity versus time v(t) graph below to answer the following questions: Vx 20...
4. Use the velocity versus time v(t) graph below to answer the following questions: Vx 20 m/s 10 m/s 10 s 20 s 30 s 10 m/s a. What is the displacement between 0-10 seconds? b. What is the displacement between 0-35 seconds? C. What is the acceleration at t = 10 seconds?
DATA TABLE 4 Purpose: To practice analyzing data Time t Distance (m) Optional) 0 0.50 0.75...
DATA TABLE 4 Purpose: To practice analyzing data Time t Distance (m) Optional) 0 0.50 0.75 1.00 1.25 0 0 3.1 2.8 4.8 4. 7.4 7.8 2.8 2.5 4.7 56 2.6 4.8 8.2 3.2 30 7.9 7.5 36 1.56 (d (e) The equation of motion for an object in free fall starting from rest is y gf, where g is the acceleration due to gravity. This is the equation of a parabola, which has the general form y = ar...
13. Find the magnitudes of the initial (at t 0) velocity and acceleration of the auto respectively At time t 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by -0.50t, in m/s2 for t in seconds 14. Find the time when it stops 15. Find the distance it has traveled tt the end of 4.0 s 16. Find the distance it has traveled by the time it stops
QUESTION 1 The following velocity vs time data is given. To find polynomial interpolation are the velocity at t-14.9s, the three time data points you would choose for second order ime (s Velocity (m/s) 22 O 0. 15, 18 O 15, 18, 22 O o. 15, 22 O 0, 18, 24 15 18 37 25 123 QUESTION 2 The data of velocity vs time is given. 15 18 36 24 Velocity(m/s) 23 5 The velocity in m/s att-16s using linear...
First you need to find the acceleration and then the time Please
explain how you get ( t ), which way you have used?. And why.
For
this I only have one question. Do we need to divide the distance r
1 cm by 100 to convert it to m in order to get the final answer? Or
just keep it as its.
Show all work clearly. No credit for answer only. Provide the proper units. 1. A particle of...
The wind data of a site is listed in the attached file. The data summarizes the wind speeds and their frequencies at the hub height of the turbine described below. Select a generator size that maximizes the annual energy output. Consider generator ratings in increments of 25 kw. Express the final answer in kWh. Parameters Turbine rotor diameter: 70.0 m Overall efficiency: air density low speeds: 33% 1.16 kg/m generator disengaged for the input values below 30% Site Generator cutoff...
The following data of the velocity of a body as a function of Time (s) Velocity (m/s) 22 Using quadratic interpolation, the interpolant time is given as f 24 123 4. 15 24 18 37 25 v(t) 9.500r2 -383.0t +3853 approximates the velocity of the body between 18 and 24 seconds. From $ information, can you find out when the velocity of the body is 26 m/sdurintg above time interval?
4. Use the velocity versus time v(t) graph below to answer the following questions: Vx 20 m/s 10 m/s 10 s 20 s 30 s 10 m/s a. What is the displacement between 0-10 seconds? b. What is the displacement between 0-35 seconds? C. What is the acceleration at t = 10 seconds?
DATA TABLE 4 Purpose: To practice analyzing data Time t Distance (m) Optional) 0 0.50 0.75 1.00 1.25 0 0 3.1 2.8 4.8 4. 7.4 7.8 2.8 2.5 4.7 56 2.6 4.8 8.2 3.2 30 7.9 7.5 36 1.56 (d (e) The equation of motion for an object in free fall starting from rest is y gf, where g is the acceleration due to gravity. This is the equation of a parabola, which has the general form y = ar...
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