How to read an existing file content and then sort them using merge sort into (in java)
1. alphabetical
2. shortest to the longest word
// Java code for above problem
import java.util.*;
import java.io.*;
class Main
{
public static void main(String args[]) throws
Exception
{
File file = new
File("words.txt");
BufferedReader br = new
BufferedReader(new FileReader(file));
ArrayList<String> arr=new
ArrayList<String>();
String str="";
while
((str=br.readLine())!=null) // read
words from file and store them in a list
arr.add(str);
System.out.println("Before sorting:
"+arr);
mergeSort(arr,0,arr.size()-1);
// sort the list using merge sort method
System.out.println("After sorting:
"+arr);
}
public static void mergeSort(ArrayList<String>
arr, int start, int end)
{
if(start>=end)
return;
int middle=(start+end)/2;
mergeSort(arr,start,middle);
mergeSort(arr,middle+1,end);
merge(arr,start,middle,end);
}
public static void merge(ArrayList<String>
arr,int start,int middle,int end)
{
int n1=middle-start+1;
int n2=end-middle;
ArrayList<String> arr1=new
ArrayList<String>();
for(int i=0;i<n1;i++)
arr1.add(arr.get(start+i));
ArrayList<String> arr2=new
ArrayList<String>();
for(int i=0;i<n2;i++)
arr2.add(arr.get(middle+1+i));
int i=0,j=0,k=start;
while(i<n1 &&
j<n2)
{
int
value=arr1.get(i).compareTo(arr2.get(j));
if(value<0)
{
arr.set(k,arr1.get(i));
i++;
}
else
{
arr.set(k,arr2.get(j));
j++;
}
k++;
}
while(i<n1)
{
arr.set(k,arr1.get(i));
i++;
k++;
}
while(j<n2)
{
arr.set(k,arr2.get(j));
j++;
k++;
}
}
}
Sample output:
let "words.txt" has following data:
aaa
abcd
abc
aa
a
zebra
home
my
word
sort
then following will be the output:
// Mention in comments if any mistakes or errors are found. Thank you.
How to read an existing file content and then sort them using merge sort into (in...
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