Question

Bernoulli Equation Team Problem 4) You are making home brewed beer (p=2.06 slugs/ft^3, mew=3.5*10^-5 lb*s/ft^2). As part of the process, you need to siphon the wort (fermented beer with sediment at the bottom) into a clean tank using a 0.5 inch hose. The arrangement in your kitchen had the height difference between the free surface of the wort tank and the end of the siphon tube equal to 1 foot. Assuming the flow rate is inviscid, find the flow rate in the siphon tube in gallons per min. USE BERNOULLI EQUATION!

Bernoulli Equation Team Problem 4 You are making homebrewed beer (p 2.06 slugs/ft', u 3.5x105 lb s/ft). As part of the process, you need to siphon the wort (fermented beer with sediment at the bottom) into a clean tank using a 0.5 inch hose. The arrangement in your kitchen has the height difference between the free surface of the wort tank and the end of the siphon tube equal to 1 foot. Assuming the flow is inviscid, find the flow rate in the siphon tube in [gallons per min].

Answer 1

202 - + z = constant Sg + 292 - + 2 + 2 29 Sola: As per Bernoul is equation, lo - where P = pressure head 282 = kinetic head & z = elevation . 29 > • elevation difference 2,- 22 = I ft & Pressure at both wort tank & siphon end is same as atmosphenic pressure P ( as velocity at free surface of wort tank is zero or 6 = 2,-22=1 + 24 = 20 = 2 x 32.2 = 20 = 8.025 ft/s area of cross section of hose pipe = tp= ax qis?= 0.19635 ima - flow rate a = Ar= (0-19635) ft² x 8.025 ft/s or a = 0.0109424 ft/s ft's = 448.831169 gpm » d = 0.0109424 x 448-031169 = 4.91 gpm) 122 * Assumption in above solution : no losses in pibe due to friction