Question

You make 1,000 L of an aqueous solution that contains 35.0 g of sucrose (C12H22011). (a) What is the molarity of sucrose in this solution? (b) How many liters of water would you have to add to this solution to reduce the molarity you calculated in part (a) by a factor of two?

Answer 1

Molarity (M): Molarity is defined as number of moles of solute dissolved in one liter of solution. Moles of solute Volume of solution (2) 1 Molarity = N D (a) weight of sucrose = 359.. Molar mass of sucrose 342 glonel volume of solution - 1000L! Moles 6 rose = 359 342 g/mol = 35 mol 342 Molarity = 35 mol 342 x1000L. Molacity = 1.02x 10-4M

(6) 4 Molarity of 2. what volume solution is reduce by factor would be the added from Molarity formula Molarity a - t volume of solution. MV = constant. Mivi = M₂ V2. Whel Mi = Molarity of solution in part (a). V = volume of aqueous solution in (a). M₂ = Molarity after addition of water. V = Total volume of solution Added volume of water = V₂ - vil M2 = MI = 1.02x109 m. 2 1.0204 M x 1000L = 1.02x10 m XV. 2. 1 V₂ = 2000L Added volume of watu to solution (0) = V-VI = 2000L-1000L =1000L 1000 L of water we have to add to this solution to reduce molarity by factor of 2