Answer a) 1.753
For 90% Confidence Interval, α = 0.10
Degrees of freedom df = 16-1 = 15
Critical t value = tα/2 = t0.05
From the table, it can be seen
t0.05 for df = 15 is 1.753
Answer b) 1.708
For 90% Confidence Interval, α = 0.10
Degrees of freedom df = 26-1 = 25
Critical t value = tα/2 = t0.05
From the table, it can be seen
t0.05 for df = 25 is 1.708
Answer c) 2.787
For 99% Confidence Interval, α = 0.01
Degrees of freedom df = 26-1 = 25
Critical t value = tα/2 = t0.005
From the table, it can be seen
t0.005 for df = 25 is 2.787
Using a 1 distribution table or software or a calculator, report the t-statistic which is multiplied...
Using a t-distribution table or software or a calculator, report the t-statistic which is multiplied by the standard error to form the margin of error for the following cases. a.90% confidence interval for a mean with15 observations. b. 90% confidence interval for a mean with 25 observations. c.98%confidence interval for a mean with 25 observations.
w e Using a 1-distribution table or software or a calculator, report the statistic which is multiplied by the standard error to form the margin or error forto a. 95% confidence interval for a mean with 15 observations b. 95% confidence interval for a mean with 25 observations c. 90confidence interval for a mean with 25 observations 1 Click the icon to view the distribution tablo a.t= Round to three decimal places as needed)
1) For the t distribution with 16 degrees of freedom, find the value for which the upper tail area is 0.005. 2) For the t distribution with 13 degrees of freedom, calculate P(T < 1.771). 3) In order to estimate the average electric usage per month, a sample of 45 houses were selected and the electric usage determined. The sample mean is 2,000 KWH. Assume a population standard deviation of 101 kilowatt hours. At 90% confidence, compute the margin of...
3. Using the t-distribution table posted on Moodle, find the df & critical t-values given N & the confidence level: N 30, 90% confidence level b. N 17, 90% confidence level c. N 23, 95% confidence level d. N 42, 99% confidence level e. N o 1,95% confidence level a. t-distribution Table TABLE D Thet distribution* Confidence interval percents (two-tailed) 80% 90% 95% 98% 99% 99.9% a level for two-tailed test 20 .10 .05 02 01 .001 a level for...
I ONLY NEED HELP WITH PART OF PART "B" I've figured out the test statistic is -1.73 and the degrees of freedom are 5. However, I'm having a hard time finding the P value via the chart (which I'm required to learn how to do).I think the chart immediately bellow this is the one used to find the p-value. However, I know at least one (or more) of the charts bellow is what's used. Please let me know which chart...
I ONLY NEED HELP WITH PART OF PART "B" I've figured out the test statistic is -1.73 and the degrees of freedom are 5. However, I'm having a hard time finding the P value via the chart (which I'm required to learn how to do).I think the chart immediately bellow this is the one used to find the p-value. However, I know at least one (or more) of the charts bellow is what's used. Please let me know which chart...