Question

i would really appreciate a quick answer please, thank you

2. A 82.5 g sample of iron bar is placed in a coffee cup calorimeter containing 150 ml of water at 22.6 °C. The final temperature of the water and the iron bar is 40.0°C. Assume that the heat capacity of the calorimeter is negligible. (SFe=0.444 J/g °C, SH2o = 4.184 Jlg °C). Report answers to 3 sf (significant figures). a. Calculate the initial temperature (°C) of the iron bar. (4 marks) b. Determine the heat capacity (J/°C) of the iron bar. (3 marks)

Answer 1

- © mass of iron bere = 82.59 water = 150ml 1 mass of water = 150 me x lg 1 ml = 150g 1 penumirey doboz Igle) Find terferohre = 400 let initial terpercn of iron ber = TC. het released by iron ban = mis tarta) = 82.59* 01 444 317&x (T-405€ = 36.6317-40) J so heat af Now, a equilibrium on temen sy water = m.s(t-fo) = 1509x 41843\Á 2x(40- 22.69€ = "109205 equilibrium - heat tamen by water = heat released by cron ban 36.63 (7–40)} = 10920 | 7-40 = 298112 .. I - 338.12 initial temperahu of crón bar = 338.12. . So, 1. bar zz 49 ,109205 heet abait. of iron 298. 12°C - 36.63316