Question

A solenoid with 1200 turns per meter has a diameter of 4.00 cm. A current I = 2.63 A flows in the clockwise direction in the solenoid. A rectangular loop of length L = 16.0 cm, width w = 12.5 cm, and 2 turns is centered on the axis of the solenoid. (a) Find the magnitude of the magnetic flux through the loop. What is the area over which the flux has a non-zero value? Wb (b) When the current is increased to 5.54 A, the magnitude of the induced emf in the rectangular loop is 116 mv. How long did it take for the current to get to this value? What is the magnitude of the change in flux? How is the induced emf related to the change in flux? ms (c) What is the direction of the induced current in the rectangular loop as viewed from the location P? counterclockwise clockwise O no current

Answer 1

Given donar No of turns (u) = 1200 diameter (at) = 4:00x10m Radius (4) 2x10²m Current (I) - 2.63 A length (L) = 16.0x102 m width (w) & 128x10²m. using equation! Flux, (p = B.A.) - for B - pont

(a from eq.& 0 and V. 0 = (von I) A. Ar Area solenoid - tv2 6:14) (2x172)2 = 1.256x103 m² 0 = (4x exc67)(1000) (2-63)( 1.256x103) 16 = 4.98 X100 T-me. ab Given current I= 5.54A &avo 116mv. and N=2, - Ubrosu change in tluris given by 사 We knowo, 10 = N(Hon I) A -

using a 3 and we can write of & Noon 2) A -Nom II) A At Ata quonIN ACIL-I) { - = (4x3.14 X107)( (200)(2) C6256x173) (5.54 -2.63 (116 x103) 11oxios 116x103 - 9.49x105 seconds. = 0.95 mvr