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A motorbike performs the'' loop the loop' 'stunt where it travels in vertical circular motion. At...

A motorbike performs the'' loop the loop' 'stunt where it travels in vertical circular motion. At the top of the circle the centripetal force is fn+mg=mv^2/r. It must have a minimum speed to stay on the track. The book says to minimise velocity the normal force has to equal zero. My question is how can a normal force be zero if something has to be oppose the static frictional force.

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Answer #1

This is a verticle circular motion, in All calculation we ignore all friction, (In Horizontal we consider friction) Normal (F

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