Determine if you are to use a normal distribution, a t-distribution, or a population proportion. Then,...
In a survey of 639 males ages 18-64, 398 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. The 90% confidence interval for the population proportion p is ( nothing, nothing). (Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is...
In a survey of 628 males ages 18-64, 394 say they have gone to the dentist in the past year. oportion n er re the results and compare he wa ns onstruct 90% and 95% confidence intervals or the population The 90% confidence interval for the population proportion p is ( Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is (Round to three decimal places as needed.) Interpret your results of both...
In a survey of 609 males ages 18-64, 395 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. The 90% confidence interval for the population proportion p is ( , ). (Round to three decimal places as needed.)
12.22 The paper "The Effects of Adolescent Volunteer Activities on the Perception of Local Society and Community Spirit Mediated by Self-Conception" (Advanced Science and Technology Letters [2016]: 19-23) describes a survey of a large representative sample of middle school children in South Korea. One question in the survey asked how much time per year the children spent in volunteer activities. The sample mean was 14.76 hours and the sample standard deviation population mean even though the population distribution is not...
In a survey of 662 males ages 18-64, 397 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. The 90% confidence interval for the population proportion p is ( nothing, nothing). (Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is...
Use the standard normal distribution or the t-distribution to construct the indicated confidence interval for the population mean of each data set. Justify your decision. If neither distribution can be used, explain why. Interpret the results. (a) In a random sample of 36 patients, the mean waiting time at a dentist’s office was 24 minutes and the standard deviation was 7.5 minutes. Construct a 90% confidence interval for the population mean. (b) In a random sample of 25 cereal boxes,...
24. Find the minimum sample size required to estimate a population proportion with a margin of error = 0.05 a confidence level of 90%, and from a prior study, p is estimated to be .25 (a) 203 (b) 329 (c) 247 (d) 396 (e) 289 25. In a survey of 385 students at Broward College, North Campus, results revealed that 154 students were born outside of the USA. Construct a 96% confidence interval estimate for the proportion of students who...
This Quiz: 22 pts possit Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 40 people, the mean body mass index (BMI) was 26.9 and the standard deviation was 6.03. O A. Use a normal distribution because the sample is random, the population is normal, and is known O B. Use a...
7. Determine whether a normal distribution or a normal distribution or t distribution should be used or whether neither of should be used to construct a confidence interval for the mean. (Section 6.2) Circle the correct answer. in a random sample of 22 families, the mean weekly food expense was $95.60 with a sample standard deviation of $22.50. Assume the weekly food expense is normally distributed. A) Normal distribution B) t-distribution C) Neither For a sample of 20 IQ scores...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...