5)
Molecular weight of NH4NO2 64.06 g/mol
Moles of NH4NO3 = 10 g /80 g/mol == 0.125 moles
So, moles of nitrogen = 2 x 0.125 = 0.250 moles
1 mole contain 6.022 x 1023 atoms
0.312 moles contain = 0.250 x 6.022 x 1023 atoms == 1.51 x 1023 atoms
(6)
given average value = 63.5 amu
so,
69.1 % x 62.9 amu + 30.1% x Cu = 100%x 63.5 amu
Cu = 63500-(69.1 % x 62.9 amu ) / 30.1
= 64.8 amu
please post remaining questions separately. Only one question need to be answered according to HOMEWORKLIB RULES
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