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Show that if f (x - 1) = -f 6 - x), S“ f (x - 2) dx = 0. Hint: You may find it useful to make the variable substitution, u =
0 0
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ng at 12-= .- Hi q-u) f(1) = - +(-u) ~ fintf(-4)=0 Iz < 404-4) aus į - - +(+) dat S f(-6df =\-( 8(t) && ( from *) herme J is

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