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Physics SP2019 CHD4 Problem 18.9 Review Part A 4.7 mol of pold is shepod into a sphere. What is the sphores diametor? Expres
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Answer #1

molecular mass of gold , m = 197 gm/mol

density , p = 19320 Kg/m^3

mass of gold , m = 4.7 * 0.197 Kg

m = 0.9259 Kg

NOw, let the diameter is D

as volume = mass/density

4pi/3 * (D/2)^2 = 0.9259/19320

solving for D

D = 0.00676 m = 0.676 cm

the diameter of sphere is 0.676 cm

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