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a) Given AE = 5, ED = 3 and DC = 6, calculate the following. 40=8.39 В р. Figure 1: A Right angled triangle. i) LAEB ii) AC i
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B FOR SADC & 180-90-53² LDAC 37° on AS ABED A Right Angle Talangle, AB 2 AE Cos 370 AB = 5X 637 AB ~ 3.99 & 4 BEZ AEsin379 -

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