Question

Please answer both questions, thank you!

Use the elimination method to find all solutions of the system S y2 The four solutions of the system are: the one with < 0, y< 0 is 2 - = 4 Preview Preview = the one with < 0, y > 0 is Preview Preview y= the one with > 0, y< 0 is Preview Preview the one with x > 0, y > 0 is Preview T= Preview y= Get help: Video Submit Question 30. Points possible: 3 This is attempt 1 of 3. Message instructor about this question Use the elimination method to find all solutions of the system 32y2 11 l 22 +4y2 8 The four solutions of the system are: (- a, - b), ( - a, b), (a, b), and (a, b) with positive numbers - and b=+-1 Preview Preview +-2 a= Get help: Video

Answer 1

Use the elimination method to find all solutions of the system J2y9 y24 The four solutions of the system are: Ans. x2y29 andx -y -4 13 2x-13x=, 2 13 13 5 9 2 xy +y9y2 2 9- =- 2 13 5 13 5 13 5 Solution:2 H 2 2 V2 13 5 the one with r < 0, y < 0 is Ans. 13 2 5 y the one with r < 0, y> 0 is Ans.

13 2 y 0, y < 0 is the one with Ans. 13 2 y 12 the one with r > 0, y > 0 is 2 y nI

Use the elimination method to find all solutions of the system 32-y211 l2+4y2 8 The four solutions of the system are: (- a, b), (-a, b), (a, b), and (a, b) with positive numbers Preview and b Preview +-2 +-1 Ans. 3x2 -y-1112x2-4y 44 x4y-8 13x252x=4>x - 12 3x2-y-113(2) -y =11 y- 1-y- a 2,b 1