In Python
Write a program to fill a square list with 5 rows and 5 columns, placing the integer 1 along the diagonal.
Print the list.
Here is what the output should look like:
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
0 0 0 0 1
Answer:
Explanation:
First te square list l is created using nested loops, whenever i equals j, 1 is appended , otherwise 0 is appended to the row. temp list denotes each row which is finally appended to the l everytime after inner loop exits.
Then, another nested loop is used to print the square list as mentioned below.
Please provide comments if you have any doubts!
Code:
l = []
for i in range(5):
temp =[]
for j in range(5):
if(i==j):
temp.append(1)
else:
temp.append(0)
l.append(temp)
for i in range(5):
for j in range(5):
print(l[i][j], end = ' ')
print()
Output:
PLEASE UPVOTE IF YOU FOUND THIS HELPFUL!
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